Distance from Jefferson Valley-Yorktown to Norton Shores
The shortest distance (air line) between Jefferson Valley-Yorktown and Norton Shores is 648.87 mi (1,044.26 km).
How far is Jefferson Valley-Yorktown from Norton Shores
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 15:12 (08.12.2025)
Norton Shores is located in Michigan, United States within 43° 9' 43.56" N -87° 44' 53.16" W (43.1621, -86.2519) coordinates. The local time in Norton Shores is 15:12 (08.12.2025)
The calculated flying distance from Norton Shores to Norton Shores is 648.87 miles which is equal to 1,044.26 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Norton Shores, Michigan, United States