Distance from Jefferson Valley-Yorktown to Oxon Hill
The shortest distance (air line) between Jefferson Valley-Yorktown and Oxon Hill is 242.22 mi (389.82 km).
How far is Jefferson Valley-Yorktown from Oxon Hill
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 16:56 (08.12.2025)
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 16:56 (08.12.2025)
The calculated flying distance from Oxon Hill to Oxon Hill is 242.22 miles which is equal to 389.82 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Oxon Hill, Maryland, United States