Distance from Jefferson Valley-Yorktown to Port Arthur
The shortest distance (air line) between Jefferson Valley-Yorktown and Port Arthur is 1,375.03 mi (2,212.90 km).
How far is Jefferson Valley-Yorktown from Port Arthur
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 01:52 (11.12.2025)
Port Arthur is located in Texas, United States within 29° 51' 19.44" N -94° 4' 24.96" W (29.8554, -93.9264) coordinates. The local time in Port Arthur is 00:52 (11.12.2025)
The calculated flying distance from Port Arthur to Port Arthur is 1,375.03 miles which is equal to 2,212.90 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Port Arthur, Texas, United States