Distance from Jefferson Valley-Yorktown to Prospect Heights
The shortest distance (air line) between Jefferson Valley-Yorktown and Prospect Heights is 729.78 mi (1,174.47 km).
How far is Jefferson Valley-Yorktown from Prospect Heights
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 23:20 (12.12.2025)
Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 22:20 (12.12.2025)
The calculated flying distance from Prospect Heights to Prospect Heights is 729.78 miles which is equal to 1,174.47 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Prospect Heights, Illinois, United States