Distance from Jefferson Valley-Yorktown to Providence
The shortest distance (air line) between Jefferson Valley-Yorktown and Providence is 127.98 mi (205.96 km).
How far is Jefferson Valley-Yorktown from Providence
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 21:35 (12.12.2025)
Providence is located in Rhode Island, United States within 41° 49' 22.8" N -72° 34' 52.68" W (41.8230, -71.4187) coordinates. The local time in Providence is 21:35 (12.12.2025)
The calculated flying distance from Providence to Providence is 127.98 miles which is equal to 205.96 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Providence, Rhode Island, United States