Distance from Jefferson Valley-Yorktown to Riegelsberg
The shortest distance (air line) between Jefferson Valley-Yorktown and Riegelsberg is 3,772.21 mi (6,070.79 km).
How far is Jefferson Valley-Yorktown from Riegelsberg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 19:56 (10.03.2025)
Riegelsberg is located in Regionalverband Saarbrücken, Germany within 49° 17' 39.12" N 6° 56' 15" E (49.2942, 6.9375) coordinates. The local time in Riegelsberg is 01:56 (11.03.2025)
The calculated flying distance from Riegelsberg to Riegelsberg is 3,772.21 miles which is equal to 6,070.79 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Riegelsberg, Regionalverband Saarbrücken, Germany