Distance from Jefferson Valley-Yorktown to Ronnenberg
The shortest distance (air line) between Jefferson Valley-Yorktown and Ronnenberg is 3,793.97 mi (6,105.81 km).
How far is Jefferson Valley-Yorktown from Ronnenberg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 21:11 (10.03.2025)
Ronnenberg is located in Region Hannover, Germany within 52° 19' 9.84" N 9° 39' 20.16" E (52.3194, 9.6556) coordinates. The local time in Ronnenberg is 03:11 (11.03.2025)
The calculated flying distance from Ronnenberg to Ronnenberg is 3,793.97 miles which is equal to 6,105.81 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Ronnenberg, Region Hannover, Germany