Distance from Jefferson Valley-Yorktown to Rosenberg
The shortest distance (air line) between Jefferson Valley-Yorktown and Rosenberg is 1,475.98 mi (2,375.37 km).
How far is Jefferson Valley-Yorktown from Rosenberg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 22:30 (15.12.2025)
Rosenberg is located in Texas, United States within 29° 32' 44.16" N -96° 10' 39.72" W (29.5456, -95.8223) coordinates. The local time in Rosenberg is 21:30 (15.12.2025)
The calculated flying distance from Rosenberg to Rosenberg is 1,475.98 miles which is equal to 2,375.37 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Rosenberg, Texas, United States