Distance from Jefferson Valley-Yorktown to Ruskin
The shortest distance (air line) between Jefferson Valley-Yorktown and Ruskin is 1,059.45 mi (1,705.02 km).
How far is Jefferson Valley-Yorktown from Ruskin
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 15:51 (15.12.2025)
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 15:51 (15.12.2025)
The calculated flying distance from Ruskin to Ruskin is 1,059.45 miles which is equal to 1,705.02 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Ruskin, Florida, United States