Distance from Jefferson Valley-Yorktown to Safety Harbor
The shortest distance (air line) between Jefferson Valley-Yorktown and Safety Harbor is 1,048.01 mi (1,686.60 km).
How far is Jefferson Valley-Yorktown from Safety Harbor
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 06:29 (16.12.2025)
Safety Harbor is located in Florida, United States within 28° 0' 28.8" N -83° 18' 12.96" W (28.0080, -82.6964) coordinates. The local time in Safety Harbor is 06:29 (16.12.2025)
The calculated flying distance from Safety Harbor to Safety Harbor is 1,048.01 miles which is equal to 1,686.60 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Safety Harbor, Florida, United States