Distance from Jefferson Valley-Yorktown to San Angelo
The shortest distance (air line) between Jefferson Valley-Yorktown and San Angelo is 1,623.19 mi (2,612.27 km).
How far is Jefferson Valley-Yorktown from San Angelo
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 01:01 (17.12.2025)
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 00:01 (17.12.2025)
The calculated flying distance from San Angelo to San Angelo is 1,623.19 miles which is equal to 2,612.27 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
San Angelo, Texas, United States