Distance from Jefferson Valley-Yorktown to San Jose
The shortest distance (air line) between Jefferson Valley-Yorktown and San Jose is 2,550.73 mi (4,105.01 km).
How far is Jefferson Valley-Yorktown from San Jose
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 05:36 (16.12.2025)
San Jose is located in California, United States within 37° 18' 4.32" N -122° 9' 7.2" W (37.3012, -121.8480) coordinates. The local time in San Jose is 02:36 (16.12.2025)
The calculated flying distance from San Jose to San Jose is 2,550.73 miles which is equal to 4,105.01 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
San Jose, California, United States