Distance from Jefferson Valley-Yorktown to Sansepolcro
The shortest distance (air line) between Jefferson Valley-Yorktown and Sansepolcro is 4,174.84 mi (6,718.76 km).
How far is Jefferson Valley-Yorktown from Sansepolcro
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 14:58 (25.03.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 20:58 (25.03.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,174.84 miles which is equal to 6,718.76 km.
Jefferson Valley-Yorktown, New York, United States