Distance from Jefferson Valley-Yorktown to Sapulpa
The shortest distance (air line) between Jefferson Valley-Yorktown and Sapulpa is 1,253.67 mi (2,017.59 km).
How far is Jefferson Valley-Yorktown from Sapulpa
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 10:47 (18.12.2025)
Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 09:47 (18.12.2025)
The calculated flying distance from Sapulpa to Sapulpa is 1,253.67 miles which is equal to 2,017.59 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Sapulpa, Oklahoma, United States