Distance from Jefferson Valley-Yorktown to Sassenberg
The shortest distance (air line) between Jefferson Valley-Yorktown and Sassenberg is 3,740.57 mi (6,019.87 km).
How far is Jefferson Valley-Yorktown from Sassenberg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 11:57 (11.03.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 17:57 (11.03.2025)
The calculated flying distance from Sassenberg to Sassenberg is 3,740.57 miles which is equal to 6,019.87 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Sassenberg, Warendorf, Germany