Distance from Jefferson Valley-Yorktown to Sassenburg
The shortest distance (air line) between Jefferson Valley-Yorktown and Sassenburg is 3,825.83 mi (6,157.07 km).
How far is Jefferson Valley-Yorktown from Sassenburg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 12:27 (11.03.2025)
Sassenburg is located in Gifhorn, Germany within 52° 31' 0.12" N 10° 37' 59.88" E (52.5167, 10.6333) coordinates. The local time in Sassenburg is 18:27 (11.03.2025)
The calculated flying distance from Sassenburg to Sassenburg is 3,825.83 miles which is equal to 6,157.07 km.
Jefferson Valley-Yorktown, New York, United States