Distance from Jefferson Valley-Yorktown to Seabrook
The shortest distance (air line) between Jefferson Valley-Yorktown and Seabrook is 228.06 mi (367.03 km).
How far is Jefferson Valley-Yorktown from Seabrook
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 13:29 (18.12.2025)
Seabrook is located in Maryland, United States within 38° 58' 48.72" N -77° 8' 59.28" W (38.9802, -76.8502) coordinates. The local time in Seabrook is 13:29 (18.12.2025)
The calculated flying distance from Seabrook to Seabrook is 228.06 miles which is equal to 367.03 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Seabrook, Maryland, United States