Distance from Jefferson Valley-Yorktown to Secaucus
The shortest distance (air line) between Jefferson Valley-Yorktown and Secaucus is 39.59 mi (63.72 km).
How far is Jefferson Valley-Yorktown from Secaucus
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 10:47 (18.12.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:47 (18.12.2025)
The calculated flying distance from Secaucus to Secaucus is 39.59 miles which is equal to 63.72 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Secaucus, New Jersey, United States