Distance from Jefferson Valley-Yorktown to Shakopee
The shortest distance (air line) between Jefferson Valley-Yorktown and Shakopee is 1,019.08 mi (1,640.05 km).
How far is Jefferson Valley-Yorktown from Shakopee
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 20:50 (07.01.2026)
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 19:50 (07.01.2026)
The calculated flying distance from Shakopee to Shakopee is 1,019.08 miles which is equal to 1,640.05 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Shakopee, Minnesota, United States