Distance from Jefferson Valley-Yorktown to Sunrise
The shortest distance (air line) between Jefferson Valley-Yorktown and Sunrise is 1,111.36 mi (1,788.56 km).
How far is Jefferson Valley-Yorktown from Sunrise
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 12:48 (14.01.2026)
Sunrise is located in Florida, United States within 26° 9' 16.92" N -81° 42' 1.08" W (26.1547, -80.2997) coordinates. The local time in Sunrise is 12:48 (14.01.2026)
The calculated flying distance from Sunrise to Sunrise is 1,111.36 miles which is equal to 1,788.56 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Sunrise, Florida, United States