Distance from Jeffersontown to Buggenhout
The shortest distance (air line) between Jeffersontown and Buggenhout is 4,224.55 mi (6,798.76 km).
How far is Jeffersontown from Buggenhout
Jeffersontown is located in Kentucky, United States within 38° 12' 17.64" N -86° 25' 47.64" W (38.2049, -85.5701) coordinates. The local time in Jeffersontown is 04:50 (12.02.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 10:50 (12.02.2025)
The calculated flying distance from Buggenhout to Buggenhout is 4,224.55 miles which is equal to 6,798.76 km.
Jeffersontown, Kentucky, United States
Related Distances from Jeffersontown
Buggenhout, Arr. Dendermonde, Belgium