Distance from Jeffersontown to Diepenbeek
The shortest distance (air line) between Jeffersontown and Diepenbeek is 4,274.80 mi (6,879.63 km).
How far is Jeffersontown from Diepenbeek
Jeffersontown is located in Kentucky, United States within 38° 12' 17.64" N -86° 25' 47.64" W (38.2049, -85.5701) coordinates. The local time in Jeffersontown is 23:52 (14.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 05:52 (15.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,274.80 miles which is equal to 6,879.63 km.
Jeffersontown, Kentucky, United States
Related Distances from Jeffersontown
Diepenbeek, Arr. Hasselt, Belgium