Distance from Jeffersontown to Opglabbeek
The shortest distance (air line) between Jeffersontown and Opglabbeek is 4,276.74 mi (6,882.75 km).
How far is Jeffersontown from Opglabbeek
Jeffersontown is located in Kentucky, United States within 38° 12' 17.64" N -86° 25' 47.64" W (38.2049, -85.5701) coordinates. The local time in Jeffersontown is 02:29 (15.02.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 08:29 (15.02.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,276.74 miles which is equal to 6,882.75 km.
Jeffersontown, Kentucky, United States
Related Distances from Jeffersontown
Opglabbeek, Arr. Maaseik, Belgium