Distance from Jeffersontown to Sint-Andries
The shortest distance (air line) between Jeffersontown and Sint-Andries is 4,178.83 mi (6,725.17 km).
How far is Jeffersontown from Sint-Andries
Jeffersontown is located in Kentucky, United States within 38° 12' 17.64" N -86° 25' 47.64" W (38.2049, -85.5701) coordinates. The local time in Jeffersontown is 09:44 (15.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 15:44 (15.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,178.83 miles which is equal to 6,725.17 km.
Jeffersontown, Kentucky, United States
Related Distances from Jeffersontown
Sint-Andries, Arr. Brugge, Belgium