Distance from Jeffersonville to Begijnendijk
The shortest distance (air line) between Jeffersonville and Begijnendijk is 4,245.51 mi (6,832.49 km).
How far is Jeffersonville from Begijnendijk
Jeffersonville is located in Indiana, United States within 38° 20' 15.36" N -86° 17' 50.64" W (38.3376, -85.7026) coordinates. The local time in Jeffersonville is 11:10 (02.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 17:10 (02.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,245.51 miles which is equal to 6,832.49 km.
Jeffersonville, Indiana, United States
Related Distances from Jeffersonville
Begijnendijk, Arr. Leuven, Belgium