Distance from Jeffersonville to Diepenbeek
The shortest distance (air line) between Jeffersonville and Diepenbeek is 4,273.53 mi (6,877.58 km).
How far is Jeffersonville from Diepenbeek
Jeffersonville is located in Indiana, United States within 38° 20' 15.36" N -86° 17' 50.64" W (38.3376, -85.7026) coordinates. The local time in Jeffersonville is 13:46 (02.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 19:46 (02.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,273.53 miles which is equal to 6,877.58 km.
Jeffersonville, Indiana, United States
Related Distances from Jeffersonville
Diepenbeek, Arr. Hasselt, Belgium