Distance from Jeffersonville to Kalmthout
The shortest distance (air line) between Jeffersonville and Kalmthout is 4,221.91 mi (6,794.51 km).
How far is Jeffersonville from Kalmthout
Jeffersonville is located in Indiana, United States within 38° 20' 15.36" N -86° 17' 50.64" W (38.3376, -85.7026) coordinates. The local time in Jeffersonville is 17:09 (02.02.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 23:09 (02.02.2025)
The calculated flying distance from Kalmthout to Kalmthout is 4,221.91 miles which is equal to 6,794.51 km.
Jeffersonville, Indiana, United States
Related Distances from Jeffersonville
Kalmthout, Arr. Antwerpen, Belgium