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      Distance from Jessup to Villanueva de la Serena

      The shortest distance (air line) between Jessup and Villanueva de la Serena is 3,702.70 mi (5,958.92 km).

      How far is Jessup from Villanueva de la Serena

      Jessup is located in Maryland, United States within 39° 8' 55.68" N -77° 13' 22.08" W (39.1488, -76.7772) coordinates. The local time in Jessup is 16:08 (12.03.2025)

      Villanueva de la Serena is located in Badajoz, Spain within 38° 58' 0.12" N -6° 12' 0" W (38.9667, -5.8000) coordinates. The local time in Villanueva de la Serena is 22:08 (12.03.2025)

      The calculated flying distance from Villanueva de la Serena to Villanueva de la Serena is 3,702.70 miles which is equal to 5,958.92 km.

      Jessup, Maryland, United States

      Related Distances from Jessup

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      Jessup to Denver (Colorado)1,493.44 mi (2,403.47 km)
      Jessup to Brooklyn (New York)182.26 mi (293.32 km)
      Jessup to New York (New York)185.04 mi (297.80 km)
      Jessup to Phoenix (Arizona)1,989.23 mi (3,201.35 km)
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      Jessup to Los Angeles (California)2,313.86 mi (3,723.80 km)
      Jessup to Seattle (Washington)2,324.97 mi (3,741.68 km)
      Jessup to Portland (Oregon)2,350.89 mi (3,783.39 km)
      Jessup to San Francisco (California)2,446.51 mi (3,937.28 km)
      Jessup to Washington (District of Columbia)21.19 mi (34.11 km)
      Jessup to Queens (New York)192.71 mi (310.14 km)
      Jessup to Boston (Massachusetts)369.70 mi (594.97 km)
      Jessup to Detroit (Michigan)399.21 mi (642.46 km)
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      Villanueva de la Serena, Badajoz, Spain

      Related Distances to Villanueva de la Serena