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      Distance from Johns Creek to Sint-Katelijne-Waver

      The shortest distance (air line) between Johns Creek and Sint-Katelijne-Waver is 4,384.55 mi (7,056.26 km).

      How far is Johns Creek from Sint-Katelijne-Waver

      Johns Creek is located in Georgia, United States within 34° 1' 59.88" N -85° 47' 50.28" W (34.0333, -84.2027) coordinates. The local time in Johns Creek is 12:03 (23.01.2025)

      Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 18:03 (23.01.2025)

      The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,384.55 miles which is equal to 7,056.26 km.

      Johns Creek, Georgia, United States

      Related Distances from Johns Creek

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      Johns Creek to Portland (Oregon)2,165.70 mi (3,485.36 km)
      Johns Creek to Seattle (Washington)2,174.72 mi (3,499.87 km)
      Johns Creek to Atlanta (Georgia)22.53 mi (36.25 km)
      Johns Creek to Tampa (Florida)430.01 mi (692.03 km)
      Johns Creek to St. Louis (Missouri)462.65 mi (744.56 km)
      Johns Creek to Washington (District of Columbia)521.92 mi (839.95 km)
      Johns Creek to Baltimore (Maryland)555.97 mi (894.75 km)
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      Sint-Katelijne-Waver, Arr. Mechelen, Belgium

      Related Distances to Sint-Katelijne-Waver