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      Distance from Johns Creek to Sint-Pieters-Leeuw

      The shortest distance (air line) between Johns Creek and Sint-Pieters-Leeuw is 4,380.50 mi (7,049.74 km).

      How far is Johns Creek from Sint-Pieters-Leeuw

      Johns Creek is located in Georgia, United States within 34° 1' 59.88" N -85° 47' 50.28" W (34.0333, -84.2027) coordinates. The local time in Johns Creek is 11:47 (23.01.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 17:47 (23.01.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,380.50 miles which is equal to 7,049.74 km.

      Johns Creek, Georgia, United States

      Related Distances from Johns Creek

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      Johns Creek to St. Louis (Missouri)462.65 mi (744.56 km)
      Johns Creek to Washington (District of Columbia)521.92 mi (839.95 km)
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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw