Distance from Johnston to Koekelberg
The shortest distance (air line) between Johnston and Koekelberg is 4,371.20 mi (7,034.77 km).
How far is Johnston from Koekelberg
Johnston is located in Iowa, United States within 41° 41' 27.6" N -94° 16' 35.76" W (41.6910, -93.7234) coordinates. The local time in Johnston is 07:05 (13.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 14:05 (13.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 4,371.20 miles which is equal to 7,034.77 km.
Related Distances from Johnston
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium