Distance from Johnstown to Lyaskovets
The shortest distance (air line) between Johnstown and Lyaskovets is 5,005.90 mi (8,056.22 km).
How far is Johnstown from Lyaskovets
Johnstown is located in Pennsylvania, United States within 40° 19' 33.6" N -79° 4' 50.16" W (40.3260, -78.9194) coordinates. The local time in Johnstown is 07:38 (13.06.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 14:38 (13.06.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,005.90 miles which is equal to 8,056.22 km.
Johnstown, Pennsylvania, United States
Related Distances from Johnstown
Lyaskovets, Veliko Tarnovo, Bulgaria