Distance from Jonesboro to Sint-Katelijne-Waver
The shortest distance (air line) between Jonesboro and Sint-Katelijne-Waver is 4,550.49 mi (7,323.30 km).
How far is Jonesboro from Sint-Katelijne-Waver
Jonesboro is located in Arkansas, United States within 35° 49' 16.32" N -91° 19' 15.24" W (35.8212, -90.6791) coordinates. The local time in Jonesboro is 15:11 (23.01.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 22:11 (23.01.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,550.49 miles which is equal to 7,323.30 km.
Jonesboro, Arkansas, United States
Related Distances from Jonesboro
Sint-Katelijne-Waver, Arr. Mechelen, Belgium