Distance from Julianadorp to Cesky Tesin
The shortest distance (air line) between Julianadorp and Cesky Tesin is 636.69 mi (1,024.65 km).
How far is Julianadorp from Cesky Tesin
Julianadorp is located in Kop van Noord-Holland, Netherlands within 52° 52' 59.88" N 4° 43' 59.88" E (52.8833, 4.7333) coordinates. The local time in Julianadorp is 07:47 (19.04.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 07:47 (19.04.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 636.69 miles which is equal to 1,024.65 km.
Julianadorp, Kop van Noord-Holland, Netherlands
Related Distances from Julianadorp
Cesky Tesin, Moravskoslezský kraj, Czechia