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      Distance from Juneau to San Fernando de Henares

      The shortest distance (air line) between Juneau and San Fernando de Henares is 5,040.18 mi (8,111.38 km).

      How far is Juneau from San Fernando de Henares

      Juneau is located in Alaska, United States within 58° 27' 16.56" N -135° 49' 33.96" W (58.4546, -134.1739) coordinates. The local time in Juneau is 14:43 (08.03.2025)

      San Fernando de Henares is located in Madrid, Spain within 40° 25' 32.16" N -4° 27' 52.92" W (40.4256, -3.5353) coordinates. The local time in San Fernando de Henares is 00:43 (09.03.2025)

      The calculated flying distance from San Fernando de Henares to San Fernando de Henares is 5,040.18 miles which is equal to 8,111.38 km.

      Juneau, Alaska, United States

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      Juneau to New York (New York)2,846.07 mi (4,580.30 km)
      Juneau to Brooklyn (New York)2,847.39 mi (4,582.42 km)
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      San Fernando de Henares, Madrid, Spain

      Related Distances to San Fernando de Henares