Distance from Kernersville to Diepenbeek
The shortest distance (air line) between Kernersville and Diepenbeek is 4,157.85 mi (6,691.41 km).
How far is Kernersville from Diepenbeek
Kernersville is located in North Carolina, United States within 36° 6' 23.4" N -81° 54' 56.88" W (36.1065, -80.0842) coordinates. The local time in Kernersville is 04:46 (13.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 10:46 (13.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,157.85 miles which is equal to 6,691.41 km.
Kernersville, North Carolina, United States
Related Distances from Kernersville
Diepenbeek, Arr. Hasselt, Belgium