Distance from Kinston to Sveti Ivan Zelina
The shortest distance (air line) between Kinston and Sveti Ivan Zelina is 4,687.45 mi (7,543.73 km).
How far is Kinston from Sveti Ivan Zelina
Kinston is located in North Carolina, United States within 35° 16' 28.92" N -78° 24' 21.96" W (35.2747, -77.5939) coordinates. The local time in Kinston is 00:47 (03.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 06:47 (03.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,687.45 miles which is equal to 7,543.73 km.
Kinston, North Carolina, United States
Related Distances from Kinston
Sveti Ivan Zelina, Zagrebačka županija, Croatia