Distance from La Porte to Aleksandrow Kujawski
The shortest distance (air line) between La Porte and Aleksandrow Kujawski is 5,487.68 mi (8,831.57 km).
How far is La Porte from Aleksandrow Kujawski
La Porte is located in Texas, United States within 29° 40' 8.04" N -96° 57' 5.76" W (29.6689, -95.0484) coordinates. The local time in La Porte is 02:10 (04.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:10 (04.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,487.68 miles which is equal to 8,831.57 km.
La Porte, Texas, United States
Related Distances from La Porte
Aleksandrow Kujawski, Włocławski, Poland