Distance from La Puebla del Rio to Alexandroupoli
The shortest distance (air line) between La Puebla del Rio and Alexandroupoli is 1,720.50 mi (2,768.88 km).
How far is La Puebla del Rio from Alexandroupoli
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 16:05 (08.02.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 17:05 (08.02.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,720.50 miles which is equal to 2,768.88 km.
La Puebla del Rio, Sevilla, Spain