Distance from La Puebla del Rio to Cesky Tesin
The shortest distance (air line) between La Puebla del Rio and Cesky Tesin is 1,496.31 mi (2,408.07 km).
How far is La Puebla del Rio from Cesky Tesin
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 20:44 (11.01.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 20:44 (11.01.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 1,496.31 miles which is equal to 2,408.07 km.
La Puebla del Rio, Sevilla, Spain
Related Distances from La Puebla del Rio
Cesky Tesin, Moravskoslezský kraj, Czechia