Distance from La Puebla del Rio to Chateauneuf-les-Martigues
The shortest distance (air line) between La Puebla del Rio and Chateauneuf-les-Martigues is 725.28 mi (1,167.22 km).
How far is La Puebla del Rio from Chateauneuf-les-Martigues
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 06:27 (13.01.2025)
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 06:27 (13.01.2025)
The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 725.28 miles which is equal to 1,167.22 km.
La Puebla del Rio, Sevilla, Spain
Related Distances from La Puebla del Rio
Chateauneuf-les-Martigues, Bouches-du-Rhône, France