Distance from La Puebla del Rio to San Cesareo
The shortest distance (air line) between La Puebla del Rio and San Cesareo is 1,049.89 mi (1,689.63 km).
How far is La Puebla del Rio from San Cesareo
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 20:55 (13.02.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 20:55 (13.02.2025)
The calculated flying distance from San Cesareo to San Cesareo is 1,049.89 miles which is equal to 1,689.63 km.
La Puebla del Rio, Sevilla, Spain