Distance from La Puebla del Rio to Savigny-le-Temple
The shortest distance (air line) between La Puebla del Rio and Savigny-le-Temple is 894.33 mi (1,439.29 km).
How far is La Puebla del Rio from Savigny-le-Temple
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 02:20 (29.01.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 02:20 (29.01.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 894.33 miles which is equal to 1,439.29 km.
La Puebla del Rio, Sevilla, Spain
Related Distances from La Puebla del Rio
Savigny-le-Temple, Seine-et-Marne, France