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      Distance from Lacey to San Gregorio di Catania

      The shortest distance (air line) between Lacey and San Gregorio di Catania is 6,038.55 mi (9,718.10 km).

      How far is Lacey from San Gregorio di Catania

      Lacey is located in Washington, United States within 47° 2' 46.32" N -123° 12' 24.12" W (47.0462, -122.7933) coordinates. The local time in Lacey is 20:17 (14.03.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 05:17 (15.03.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 6,038.55 miles which is equal to 9,718.10 km.

      Lacey, Washington, United States

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      Lacey to New York (New York)2,432.66 mi (3,914.99 km)
      Lacey to Brooklyn (New York)2,432.90 mi (3,915.38 km)
      Lacey to Queens (New York)2,436.85 mi (3,921.73 km)
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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania