Distance from Lake Charles to Bissendorf
The shortest distance (air line) between Lake Charles and Bissendorf is 5,040.25 mi (8,111.50 km).
How far is Lake Charles from Bissendorf
Lake Charles is located in Louisiana, United States within 30° 12' 3.6" N -94° 47' 20.04" W (30.2010, -93.2111) coordinates. The local time in Lake Charles is 21:22 (24.02.2025)
Bissendorf is located in Osnabrück; Landkreis, Germany within 52° 13' 59.88" N 8° 10' 0.12" E (52.2333, 8.1667) coordinates. The local time in Bissendorf is 04:22 (25.02.2025)
The calculated flying distance from Bissendorf to Bissendorf is 5,040.25 miles which is equal to 8,111.50 km.
Lake Charles, Louisiana, United States
Related Distances from Lake Charles
Bissendorf, Osnabrück; Landkreis, Germany