Distance from Lake Charles to Dimitrovgrad
The shortest distance (air line) between Lake Charles and Dimitrovgrad is 5,956.06 mi (9,585.35 km).
How far is Lake Charles from Dimitrovgrad
Lake Charles is located in Louisiana, United States within 30° 12' 3.6" N -94° 47' 20.04" W (30.2010, -93.2111) coordinates. The local time in Lake Charles is 15:07 (11.02.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 22:07 (11.02.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,956.06 miles which is equal to 9,585.35 km.
Lake Charles, Louisiana, United States
Related Distances from Lake Charles
Dimitrovgrad, Pirotska oblast, Serbia