Distance from Lake Charles to Sankt Polten
The shortest distance (air line) between Lake Charles and Sankt Polten is 5,465.30 mi (8,795.55 km).
How far is Lake Charles from Sankt Polten
Lake Charles is located in Louisiana, United States within 30° 12' 3.6" N -94° 47' 20.04" W (30.2010, -93.2111) coordinates. The local time in Lake Charles is 04:45 (16.03.2025)
Sankt Polten is located in Sankt Pölten, Austria within 48° 12' 0" N 15° 37' 0.12" E (48.2000, 15.6167) coordinates. The local time in Sankt Polten is 11:45 (16.03.2025)
The calculated flying distance from Sankt Polten to Sankt Polten is 5,465.30 miles which is equal to 8,795.55 km.
Lake Charles, Louisiana, United States
Related Distances from Lake Charles
Sankt Polten, Sankt Pölten, Austria