Distance from Lake Charles to Sint-Andries
The shortest distance (air line) between Lake Charles and Sint-Andries is 4,879.84 mi (7,853.34 km).
How far is Lake Charles from Sint-Andries
Lake Charles is located in Louisiana, United States within 30° 12' 3.6" N -94° 47' 20.04" W (30.2010, -93.2111) coordinates. The local time in Lake Charles is 16:08 (14.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 23:08 (14.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,879.84 miles which is equal to 7,853.34 km.
Lake Charles, Louisiana, United States
Related Distances from Lake Charles
Sint-Andries, Arr. Brugge, Belgium