Distance from Lake Hopatcong to Asenovgrad
The shortest distance (air line) between Lake Hopatcong and Asenovgrad is 4,818.03 mi (7,753.87 km).
How far is Lake Hopatcong from Asenovgrad
Lake Hopatcong is located in New Jersey, United States within 40° 57' 35.64" N -75° 23' 26.16" W (40.9599, -74.6094) coordinates. The local time in Lake Hopatcong is 20:41 (23.01.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 03:41 (24.01.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 4,818.03 miles which is equal to 7,753.87 km.
Lake Hopatcong, New Jersey, United States