Distance from Lake Los Angeles to Sveti Ivan Zelina
The shortest distance (air line) between Lake Los Angeles and Sveti Ivan Zelina is 6,177.65 mi (9,941.96 km).
How far is Lake Los Angeles from Sveti Ivan Zelina
Lake Los Angeles is located in California, United States within 34° 36' 34.92" N -118° 9' 57.96" W (34.6097, -117.8339) coordinates. The local time in Lake Los Angeles is 11:55 (03.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 20:55 (03.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 6,177.65 miles which is equal to 9,941.96 km.
Lake Los Angeles, California, United States
Related Distances from Lake Los Angeles
Sveti Ivan Zelina, Zagrebačka županija, Croatia